Web16.(5分)f(x)定义在R上的偶函数,且x≥0时,f(x)=x3,若对任意x∈[2t﹣1,2t+3],不等式f(3x﹣t)≥8f(x)恒成立,则实数t的取值范围是. 三.解答题(共70分) 17.(12分)函数 的图象(部分)如图. (1)求f(x)解析式 (2)若 ,求cosα. WebYes - that is how it works, if you have f (x)=x² and are asked what is f (2), then you replace every instance of x in the function definition with 2 so given f (x) = x², that means f (2) = 2² …
Answered: - Suppose f: R → R is defined by the… bartleby
WebFind the range of each of the following functions. (i) f (x) = 2 – 3x, x ∈ R, x > 0. (ii) f (x) = x^2 + 2, x is a real number. (iii) f (x) = x, x is a real number. A few functions are given. We have … Web3. Let x ∈ R satisfy x 7 + 5 x 2-3 = 0. Then x is not a rational number. Solution We use proof by contradiction. Suppose x 7 + 5 x 2-3 = 0 and x is rational, so we can write x = a b where a, b ∈ Z, b > 0 with gcd(a, b) = 1. Then a b 7 + 5 a b 2-3 = 0 a 7 + 5 a 2 b 5-3 b 7 = 0 Since a and b have no common factors, they cannot both be even ... dach-area
Find the Range f(x)=3x if x<0; -3x if x>=0 Mathway
WebApr 16, 2024 · Then use the formula −b 2a. −b 2a = 0 6 = 0. the x-value of the vertex is 0. substitute it back in to get the y-value. f (0) = 3(0)2 −5 = 0 − 5 = − 5. So the vertex is (0, -5). The range is either y ≥ − 5 or y ≤ − 5. Since a is positive, the parabola opens upwards. So the range has to be y is greater than or equal to something. WebExplanation: In order to figure this out, you have to set the equation to 0. f (x)= x3 + 3x2 −x− 3 = 0 Now looking at ... x3+3x2-6x-8=0 Three solutions were found : x = 2 x = -1 x = -4 Step by step solution : Step 1 :Equation at the end of step 1 : ( ( (x3) + 3x2) - 6x) - 8 = 0 Step 2 :Checking for a perfect ... Webjection since f(x) < f(y) for any pair x,y ∈ R with the relation x < y and for every real number y ∈ R there exists a real numbe x ∈ R such that y = f(x). b) Thefunction f isneither in-jective nor surjective since f(x+2π) = f(x) x + π 6= x,x ∈ R, and if y > 1 then there is no x ∈ R such that y = f(x). c) The function f is injective ... dac harford county